A Toronto Data Guy

Cool math expression with the numbers e, 5, and 0.5

I have discovered a pretty cool mathematical expression: 

-5*e^(5arccos((((5^(0.5))*0.5)+0.5)*0.5)*((-5/5)^0.5))

OR

Algebraic representation of the "five" formula

What is neat about this is that:

How does it work?

I relied on a few tricks while constructing it. 

  1. e^(pi*i) = -1
    an infamous formula
  2. 5arccos((((5^(0.5))*0.5)+0.5)*0.5) = pi
    Alex Williams discovered this little gem
  3. Balancing out where the square roots should go, so (-5/5)^0.5) versus (-5)^0.5) / (5^0.5).

I find sharing how math tricks are made does take away the mystery sometimes, but maybe in the future I’ll post one that other people solve.